\(\int \frac {\tan (d (a+b \log (c x^n)))}{x^3} \, dx\) [164]

Optimal result

Integrand size = 17, antiderivative size = 69 \[ \int \frac {\tan \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^3} \, dx=\frac {i}{2 x^2}-\frac {i \operatorname {Hypergeometric2F1}\left (1,\frac {i}{b d n},1+\frac {i}{b d n},-e^{2 i a d} \left (c x^n\right )^{2 i b d}\right )}{x^2} \]

[Out]

1/2*I/x^2-I*hypergeom([1, I/b/d/n],[1+I/b/d/n],-exp(2*I*a*d)*(c*x^n)^(2*I*b*d))/x^2

Rubi [A] (verified)

Time = 0.08 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.235, Rules used = {4593, 4591, 470, 371} \[ \int \frac {\tan \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^3} \, dx=\frac {i}{2 x^2}-\frac {i \operatorname {Hypergeometric2F1}\left (1,\frac {i}{b d n},1+\frac {i}{b d n},-e^{2 i a d} \left (c x^n\right )^{2 i b d}\right )}{x^2} \]

[In]

Int[Tan[d*(a + b*Log[c*x^n])]/x^3,x]

[Out]

(I/2)/x^2 - (I*Hypergeometric2F1[1, I/(b*d*n), 1 + I/(b*d*n), -(E^((2*I)*a*d)*(c*x^n)^((2*I)*b*d))])/x^2

Rule 371

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^p*((c*x)^(m + 1)/(c*(m + 1)))*Hyperg
eometric2F1[-p, (m + 1)/n, (m + 1)/n + 1, (-b)*(x^n/a)], x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rule 470

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Simp[d*(e*x)^(m +
1)*((a + b*x^n)^(p + 1)/(b*e*(m + n*(p + 1) + 1))), x] - Dist[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(b*(m +
n*(p + 1) + 1)), Int[(e*x)^m*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && NeQ[b*c - a*d, 0]
&& NeQ[m + n*(p + 1) + 1, 0]

Rule 4591

Int[((e_.)*(x_))^(m_.)*Tan[((a_.) + Log[x_]*(b_.))*(d_.)]^(p_.), x_Symbol] :> Int[(e*x)^m*((I - I*E^(2*I*a*d)*
x^(2*I*b*d))/(1 + E^(2*I*a*d)*x^(2*I*b*d)))^p, x] /; FreeQ[{a, b, d, e, m, p}, x]

Rule 4593

Int[((e_.)*(x_))^(m_.)*Tan[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*(d_.)]^(p_.), x_Symbol] :> Dist[(e*x)^(m + 1)
/(e*n*(c*x^n)^((m + 1)/n)), Subst[Int[x^((m + 1)/n - 1)*Tan[d*(a + b*Log[x])]^p, x], x, c*x^n], x] /; FreeQ[{a
, b, c, d, e, m, n, p}, x] && (NeQ[c, 1] || NeQ[n, 1])

Rubi steps \begin{align*} \text {integral}& = \frac {\left (c x^n\right )^{2/n} \text {Subst}\left (\int x^{-1-\frac {2}{n}} \tan (d (a+b \log (x))) \, dx,x,c x^n\right )}{n x^2} \\ & = \frac {\left (c x^n\right )^{2/n} \text {Subst}\left (\int \frac {x^{-1-\frac {2}{n}} \left (i-i e^{2 i a d} x^{2 i b d}\right )}{1+e^{2 i a d} x^{2 i b d}} \, dx,x,c x^n\right )}{n x^2} \\ & = \frac {i}{2 x^2}+\frac {\left (2 i \left (c x^n\right )^{2/n}\right ) \text {Subst}\left (\int \frac {x^{-1-\frac {2}{n}}}{1+e^{2 i a d} x^{2 i b d}} \, dx,x,c x^n\right )}{n x^2} \\ & = \frac {i}{2 x^2}-\frac {i \operatorname {Hypergeometric2F1}\left (1,\frac {i}{b d n},1+\frac {i}{b d n},-e^{2 i a d} \left (c x^n\right )^{2 i b d}\right )}{x^2} \\ \end{align*}

Mathematica [B] (verified)

Both result and optimal contain complex but leaf count is larger than twice the leaf count of optimal. \(147\) vs. \(2(69)=138\).

Time = 2.81 (sec) , antiderivative size = 147, normalized size of antiderivative = 2.13 \[ \int \frac {\tan \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^3} \, dx=\frac {-e^{2 i d \left (a+b \log \left (c x^n\right )\right )} \operatorname {Hypergeometric2F1}\left (1,1+\frac {i}{b d n},2+\frac {i}{b d n},-e^{2 i d \left (a+b \log \left (c x^n\right )\right )}\right )+(1-i b d n) \operatorname {Hypergeometric2F1}\left (1,\frac {i}{b d n},1+\frac {i}{b d n},-e^{2 i d \left (a+b \log \left (c x^n\right )\right )}\right )}{2 (i+b d n) x^2} \]

[In]

Integrate[Tan[d*(a + b*Log[c*x^n])]/x^3,x]

[Out]

(-(E^((2*I)*d*(a + b*Log[c*x^n]))*Hypergeometric2F1[1, 1 + I/(b*d*n), 2 + I/(b*d*n), -E^((2*I)*d*(a + b*Log[c*
x^n]))]) + (1 - I*b*d*n)*Hypergeometric2F1[1, I/(b*d*n), 1 + I/(b*d*n), -E^((2*I)*d*(a + b*Log[c*x^n]))])/(2*(
I + b*d*n)*x^2)

Maple [F]

\[\int \frac {\tan \left (d \left (a +b \ln \left (c \,x^{n}\right )\right )\right )}{x^{3}}d x\]

[In]

int(tan(d*(a+b*ln(c*x^n)))/x^3,x)

[Out]

int(tan(d*(a+b*ln(c*x^n)))/x^3,x)

Fricas [F]

\[ \int \frac {\tan \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^3} \, dx=\int { \frac {\tan \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right )}{x^{3}} \,d x } \]

[In]

integrate(tan(d*(a+b*log(c*x^n)))/x^3,x, algorithm="fricas")

[Out]

integral(tan(b*d*log(c*x^n) + a*d)/x^3, x)

Sympy [F]

\[ \int \frac {\tan \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^3} \, dx=\int \frac {\tan {\left (a d + b d \log {\left (c x^{n} \right )} \right )}}{x^{3}}\, dx \]

[In]

integrate(tan(d*(a+b*ln(c*x**n)))/x**3,x)

[Out]

Integral(tan(a*d + b*d*log(c*x**n))/x**3, x)

Maxima [F]

\[ \int \frac {\tan \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^3} \, dx=\int { \frac {\tan \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right )}{x^{3}} \,d x } \]

[In]

integrate(tan(d*(a+b*log(c*x^n)))/x^3,x, algorithm="maxima")

[Out]

integrate(tan((b*log(c*x^n) + a)*d)/x^3, x)

Giac [F]

\[ \int \frac {\tan \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^3} \, dx=\int { \frac {\tan \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right )}{x^{3}} \,d x } \]

[In]

integrate(tan(d*(a+b*log(c*x^n)))/x^3,x, algorithm="giac")

[Out]

integrate(tan((b*log(c*x^n) + a)*d)/x^3, x)

Mupad [F(-1)]

Timed out. \[ \int \frac {\tan \left (d \left (a+b \log \left (c x^n\right )\right )\right )}{x^3} \, dx=\int \frac {\mathrm {tan}\left (d\,\left (a+b\,\ln \left (c\,x^n\right )\right )\right )}{x^3} \,d x \]

[In]

int(tan(d*(a + b*log(c*x^n)))/x^3,x)

[Out]

int(tan(d*(a + b*log(c*x^n)))/x^3, x)